Reactions between certain organic (alkyl) halides and water produce alcohols. Consider the overall reaction for t-butyl bromide (2-bromo-2-methylpropane):(CH₃)₃CBr(aq) +H₂O(l) → (CH₃)₃COH(aq) + H⁺(aq) Br⁻(aq)The experimental rate law is rate = k[(CH3=₃ )₃ Br]. The accepted mechanism for the reaction is(1) (CH₃)₃C _ Br(aq) → (CH₃)₃C⁺(aq) + Br⁻(aq) [slow](2) (CH₃)₃C⁺(aq) + H₂O(l) → (CH₃)₃C _ OH₂⁺(aq) [fast](3) (CH₃)₃C - OH₂⁺(aq) → H⁺(aq) + (CH₃)₃C - OH(aq)[fast](a) Why doesn’t H₂O appear in the rate law?