How many milliliters of 0.200 M FeCl3 are needed to react with an excess of Na2S to produce 0.172 g of Fe2S3 if the percent yield for the reaction is 65.0%?
3 Na2S(aq) + 2 FeCl3(aq) → Fe2S3(s) + 6 NaCl(aq)
How many milliliters of 0.200 M FeCl3 are needed to react with an excess of Na2S to produce 0.172 g of Fe2S3 if the percent yield for the reaction is 65.0%?
3 Na2S(aq) + 2 FeCl3(aq) Fe2S3(s) + 6 NaCl(aq)
5.39 mL
6.38 mL
3.19 mL
12.7 mL