Refer back to Example 5.31. Two cars with six-cylinder engines and three with four-cylinder engines are to be driven over a 300-mile course. Let X1, ... X5 denote the resulting fuel efficiencies (mpg). Consider the linear combination Y = (X1 + X2)/2 − (X3 + X4+ X5)/3 which is a measure of the difference between four cylinder and six-cylinder vehicles. Compute P(0 ≤Y) and P(Y > − 2). [Hint: Y = a1X1 +... + a5X5, with a1 = 1/2,...,a5 = − 1/3.]