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21-05-2023
Physics

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The CVF for Cable 1 is 4.3i+5.7j+ 7.1k (N)
Based on the previous questions we know that: (check all that apply)
OFy(frame) = Fy(Cable 1) + Fy(Cable 2)
Fy for Cable 2 is 4.3 N
Fx for Cable 2 is -4.3 N
The planar tiangle for x and y is isoceles

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