S' e da is difficult (some say impossible) to evaluate exactly. But we can approximate it The integral using power series. First, find the 4th degree Taylor polynomial for f(x) = e² (centered at c-0). Then, as T₁(x) e, we can input z² to get T₁ (2²) e ≈ e²¹ ~ T₁ (x²) = So we can expect fe³dz ≈ ['T₁ (2²) dr. fe² drz Round answer to at least 6 decimal places.