2Fe + 3CusO4 --> 3Cu + Fe2(SO4)3

Before Experiment
Mass of beaker = 106.3g
Mass of beaker and iron = 147.3
Mass of Iron = 41g

After Experiment
Mass of beaker and copper = 141.8g
Mass of Copper = 35.5
Theoretical yield =
Percent yield =
How do I find the last 2? Please somkebody answer soon. Chemistry final is today this is the last thing I don't get...