If we look at (a + b)4 as an example, we see that the k 0 term is a4, the k = 1 term is 4a³b, and the k 2 term is 6a²b². It might be useful to include some of the unwritten factors in each term: • k = 0 term: • k = 1 term: a³b¹ • k=2 term: a²b² What we should notice is that the value of k in each term matches up with the power of b (and what's even more, the powers of a and b always add up to n). So, if we were to consider (a + b)6, and we wanted to determine the coefficient of a4b2, what would it be? •n =
•n- •The coefficient of a¹b2 will be _____
a) In the distributed form of (a + b)¹¹, the coefficient of a8 b³ will be ______
b). In the distributed form of (a + b)¹7, the coefficient of a6 b11 will be _____