Verify that the indicated function y = (x) is an explicit solution of the given first-order differential equation. (y-x)y=y-x + 18; y=x+6√x+5 When y = x + 6√x + 5, y' = Thus, in terms of x, (y - x)y' = y-x + 18 = *********** Since the left and right hand sides of the differential equation are equal when x + 6√x+5 is substituted for y, y = x + 6√x+ 5 is a solution. Proceed as in Example 6, by considering o simply as a function and give its domain. (Enter your answer using interval notation.) Then by considering as a solution of the differential equation, give at least one interval I of definition. O (-[infinity], -5) O(-10, -5] O (-5,00) O (-10, 5) O [-5, 5]