The functions p(t) and q(t) are continuous for every t. It is stated that sin(t) and t cannot both be solutions of the differential equation
y" + py' + qy = 0.
Which of the following imply this conclusion?
A: If sin(t) were a solution, then the other solution would have to be cos(t).
B: Both would satisfy the same initial conditions at 0, so this would violate the uniqueness theorem.
C: The statement is incorrect. There exist a pair of everywhere continuous functions p(t) and q(t) that will make sin(t) and t valid solutions.
a) None
b) Only (A)
c) Only (B)
d) Only (0)
e) (A) and (B)
f) (A) and (C)
g) (B) and (C)
h) All