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  • 25-01-2024
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Choosing the first option that is minimally acceptable or adequate when making a decision is known as

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solve for r F= k (m1m2/r^2)
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Rationalize the denominator and simplify-[tex] \frac{ \sqrt{6} }{ \sqrt{3} - \sqrt{2} } [/tex]
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Rationalize the denominator and simplify-[tex] \frac{ \sqrt{6} }{ \sqrt{3} - \sqrt{2} } [/tex]
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