Consider the function (x)=((x²)/3)+8.
In this problem you will calculate ∫[2,0]((x²)/3)+8x by using the definition
ᵇ∫ₐ (x)x=lim→[infinity][₌₁∑ⁿ(x)Δx] The summation inside the brackets is which is the Riemann sum where the sample points are chosen to be the right-hand endpoints of each sub-interval.
Calculate for (x)=x²/3+8 on the interval [0,2] and write your answer as a function of without any summation signs. You will need the summation formulas in Section 5 of your textbook.
Rs=
lim→[infinity] (Rs)=