Ammonia reacts with hypobromite, OBr, as follows:

2NH₃+3OBr−→N₂​+3Br−+3H₂​O.

Find the molarity of OBr⁻ if 1.00 mL of OBr⁻ solution reacts with 1.69 mg of NH₃ (molar mass 17.03 g/mol).