The mean family income for a random sample of 700 suburban households in Guinesstowne shows that a 90 percent confidence interval is ($47,250, $62,100). Herman is conducting a test of the null hypothesis H0: µ = 45,000 against the alternative hypothesis Ha: µ ≠ 45,000 at the α = 0.10 level of significance. Does Herman have enough information to conduct a test of the null hypothesis against the alternative? (4 points)

Yes, because $45,000 is not contained in the 90% confidence interval, the null hypothesis would not be rejected, and it could be concluded that the mean family income is not significantly different from $45,000 at the α = 0.10 level