[tex] \sqrt{x+1} = x - 1 \\ \\ x + 1 = (x - 1)^2 \\ \\ x + 1 = x^2 - 2x + 1 \\ \\ x = x^2 - 2x \\ \\ x - x^2 + 2x = 0 \\ \\ 3x - x^2 = 0 \\ \\ x(3 - x)= 0 \\ \\ x = 0,3 \\ \\ x = 0 \ is \ false \\ \\ x = 3[/tex]
The final result is, x = 3.
The solutions we gather were x = 0,3.
We dropped x = 0 from the equation since it does not become true, so we are left with x = 3.
