Respuesta :
40 - x < 3x
Simplify both sides of inequality:
−x + 40 < 3x
Subtract 3x on both sides:
−x + 40 − 3x < 3x − 3x−4x + 40 < 0
Divide both sides by -4:
-4x/-4 < -40/-4
x > 10
C. x > 10
Simplify both sides of inequality:
−x + 40 < 3x
Subtract 3x on both sides:
−x + 40 − 3x < 3x − 3x−4x + 40 < 0
Divide both sides by -4:
-4x/-4 < -40/-4
x > 10
C. x > 10
Solutions for 40 - x < 3x
To find the answer we have to solve the equation 40 - x < 3x.
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1) The first step is to add x to each side
40 < 3x+x
2) Next you simplify 3x+x. To simplify 3x+x you add the x to 3. 3x+x = 4x
40 < 4x
3) Divide both of the sides by 4
[tex] \frac{40}{4} [/tex] < x
4) Simplify the fraction [tex] \frac{40}{4} [/tex] to 10. You simplify it to ten because 40 ÷ 4 = 10.
10<x
5) Answer
x= > 10
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Now lets see the Choices
The correct choice is C.
x > 10
To find the answer we have to solve the equation 40 - x < 3x.
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1) The first step is to add x to each side
40 < 3x+x
2) Next you simplify 3x+x. To simplify 3x+x you add the x to 3. 3x+x = 4x
40 < 4x
3) Divide both of the sides by 4
[tex] \frac{40}{4} [/tex] < x
4) Simplify the fraction [tex] \frac{40}{4} [/tex] to 10. You simplify it to ten because 40 ÷ 4 = 10.
10<x
5) Answer
x= > 10
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Now lets see the Choices
The correct choice is C.
x > 10