Respuesta :
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c + 4 = t
t + 2 = 2c
c + 4 = 2c – 2
c = 2
t = 6
or
c = t - 4....................................(1)
in 2 years we have:
t + 2 = 2(c + 2)
i.........e......... t + 2 = 2c + 4
=> t - 2c = 2...........................(2)
(1) into (2) for c gives:
t - 2(t - 4) = 2
i.........e......... 8 - t = 2
so, t = 6 and c = 2
therefore, terrill is 6 and cranston is 2
and, in 2 years time they shall be 8 and 4....................................i..... terrill being twice cranston's age
i lost myself the first time i solved it
c + 4 = t
t + 2 = 2c
c + 4 = 2c – 2
c = 2
t = 6
or
c = t - 4....................................(1)
in 2 years we have:
t + 2 = 2(c + 2)
i.........e......... t + 2 = 2c + 4
=> t - 2c = 2...........................(2)
(1) into (2) for c gives:
t - 2(t - 4) = 2
i.........e......... 8 - t = 2
so, t = 6 and c = 2
therefore, terrill is 6 and cranston is 2
and, in 2 years time they shall be 8 and 4....................................i..... terrill being twice cranston's age
i lost myself the first time i solved it
Answer:
Cranston's Age: 2 years
Terril's Age: 6 years
Step-by-step explanation:
c = Cranston
t = Terril
Information we have:
c + 4 = t
t + 2 = 2c
So, if Cranston is 2 and Terril is 6, it's true as c + 4 (2 + 4) is 6 and When Cranston and Terril age 2 years, Cranston will be 4 and Terril will be 8, so Terril will be twice of Cranston's age.
*A lot of people forget the part where Cranston will ALSO age, so they get t = 10 and c = 6