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Convert this quadratic function to vertex form.
y=x^2+14x+48
Then determine the minimum value of the function.


Points: Concept Addressed:

3 = Correctly completes the square to convert the function into vertex form.

2 = Correctly determines the minimum value of the function.

Respuesta :

gmany
[tex]y=x^2+14x+48=\underbrace{x^2+2x\cdot7+7^2}_{use:(a+b)^2=a^2+2ab+b^2}-7^2+48=(x+7)^2-49+48=(x+7)^2-1[/tex]

The coordinates of the vertex:  (-7; -1).
The minimum value of the vertex is equal -1.

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