Respuesta :

PBCHEM
The question is incomplete. Complete question is attached below.

Solution:
The reaction involved in present electrochemical cell is:

Mg(s)     +       Zn2+(aq.)      ↔        Zn(s)      +      Mg2+ (aq.)

Thus, from above reaction it can be seen that 1 mole of Zn2+ produces 1 mole of Mg2+.

Thus, 2.5 moles of Mg2+(aq) ions would be produced when 2.5 moles of Zn2+(aq) will react.
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InesWalston

Answer: 2.5 moles of Mg+2

Since it is an example for intermolecular redox reaction. Here Mg gets oxidized to Mg+2 and Zn+2 gets reduced to Zn.

Mg(s)+ Zn+2(aq) -------> Mg+2(aq) + Zn(s)

From the balanced equation, 1:1 molar ratio of Mg and Zn+2. Hence 2.5 moles of Zn+2 produce 2.5 moles of Mg+2.

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