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In the above reaction,

Al is undergoing oxidation, while oxygen is undergoing reduction.

The oxidation half reaction for above reaction can be written as:

Al          →                Al3+      +       3e-

However, reactant and product has 4 Al atoms, so on multiplying above reaction by 4 we get

4Al    →       4Al3+        +         12e-

Thus, above is balanced oxidation half reaction for above reaction

Oxidation-reduction reactions are the reactions that depict the loss and gain of electrons. The oxidation half-reaction is given as 4Al → 4Al³⁺ + 12e⁻.

What is a half-reaction?

A half-reaction is the portrayal of the oxidation or the reduction of half of the redox reaction and only constitutes a single component. In oxidation reactions, the electrons are lost by the species.

The balanced chemical reaction is:

4Al (s) + 3O₂ (g) → 2Al₂O₃ (s)

Here, aluminum will undergo oxidation and oxygen will undergo reduction.

The balanced oxidation half will be given as:

4Al → 4Al³⁺ + 12e⁻

Therefore, the oxidation half-reaction shows the loss of the electron.

Learn more about oxidation half-reaction here:

https://brainly.com/question/15096134

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