Respuesta :
The answer to this question is (x+3)^2 + (y-3)^2 = 16 because
(x-2+5)^2+(y+1-4)^2=16 ⇔ (x+3)^2 + (y-3)^2 = 16
(x-2+5)^2+(y+1-4)^2=16 ⇔ (x+3)^2 + (y-3)^2 = 16
Answer:
[tex](x +3)^{2} +(y -3)^2 = 16[/tex]
Step-by-step explanation:
The given equation is an equation of circle.
[tex](x -2)^{2} + (y +1)^2 = 16[/tex]
The equation translated 5 units left and 4 units up.
Which means we have to add 5 with x and subtract 4 with y.
That is replace x by x + 5 and replace y by y - 4, we get
[tex](x+5 -2)^{2} + (y -4 +1)^2 = 16[/tex]
Now we have to simplify it.
[tex](x +3)^{2} +(y -3)^2 = 16[/tex]