Respuesta :
the balanced equation for the reaction is as follows
Fe₂O₃ + 3CO ----> 2Fe + 3CO₂
stoichiometry of Fe₂O₃ to Fe is 1:2
number of Fe moles formed - 15.5 g / 56 g/mol = 0.277 mol
if 2 mol of Fe are formed when 1 mol of Fe₂O₃ reacts
then 0.277 mol of Fe are formed when -1/2 x 0.277 mol = 0.139 mol
number of Fe₂O₃ mol reacted - 0.139 mol
mass of Fe₂O₃ required - 0.139 mol x 160 g/mol = 22.2 g
22.2 g of Fe₂O₃ required
Fe₂O₃ + 3CO ----> 2Fe + 3CO₂
stoichiometry of Fe₂O₃ to Fe is 1:2
number of Fe moles formed - 15.5 g / 56 g/mol = 0.277 mol
if 2 mol of Fe are formed when 1 mol of Fe₂O₃ reacts
then 0.277 mol of Fe are formed when -1/2 x 0.277 mol = 0.139 mol
number of Fe₂O₃ mol reacted - 0.139 mol
mass of Fe₂O₃ required - 0.139 mol x 160 g/mol = 22.2 g
22.2 g of Fe₂O₃ required
Answer:
22.1 g
Explanation:
usa test prep said so. I just took it and got it right.
