We can use the heat
equation,
Q = mcΔT
Where Q is the amount of energy transferred (J), m is
the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature
difference (°C).
According to the given data,
Q = 300 J
m = 267 g
c = ?
ΔT = 12 °C
By applying the
formula,
300 J = 267 g x c x
12 °C
c = 0.0936 J g⁻¹ °C⁻¹
Hence, specific heat of the given substance is 0.0936 J g⁻¹ °C⁻¹.
