The concentration of hydrogen ion in the 0.650 M solution of NaOH is [tex]\rm \bold 1.53\;\times\;10^-^1^4[/tex].
The [tex]\rm \bold k_w[/tex] has been the constant value and is the ionization product. The value of [tex]\rm \bold k_w[/tex] for water is [tex]\rm 1\;\times\;10^-^1^4[/tex].
[tex]\rm \bold k_w[/tex] = [tex]\rm [H^+]\;[OH^-][/tex]
In the NaOH solution, the hydroxide ion concentration has been the concentration of the solution.
Hydroxide ion concentration = 0.650 M
The hydrogen ion concentration can be calculated as:
Hydrogen ion concentration = [tex]\rm \dfrac{k_w}{[OH^-]}[/tex]
Hydrogen ion concentration = [tex]\rm \dfrac{1\;\times\;10^-^1^4}{0.650}[/tex]
Hydrogen ion concentration = [tex]\rm 1.53\;\times\;10^-^1^4[/tex] M.
The concentration of hydrogen ion in the 0.650 M solution of NaOH is [tex]\rm \bold 1.53\;\times\;10^-^1^4[/tex].
For more information about the ionization product, refer to the link:
https://brainly.com/question/12625563
