A computer randomly picks a number from the group 75, 76, 77, 78, 79. What is the probability the number selected is greater than 78 or even? Enter your answer, as a decimal, in the box.
The chance to pick something= valid picks/all possibilities of your numbers 76, 78 and 79 fulfill "even or greater than 78" and you have 5 numbers in total chance=[tex]\frac{3}{5}[/tex]=[tex] \frac{6}{10} [/tex]=0.6
So there is a 60% probability to pick a number which is even or greater than 78
For the answer to the question above, I think since there are only two numbers in the given sequence that are even or greater than 78. I think the probability would be 0.4
