Answer:
[tex]2x-y-3=0[/tex]
Step-by-step explanation:
We have been given a graph. We are asked to find the general form of equation of the given line.
We know that general form of equation is in format [tex]ax+by+c=0[/tex].
First of all, we will write equation of our given line in slope intercept form [tex]y=mx+b[/tex].
[tex]m=\frac{3--3}{3-0}[/tex]
[tex]m=\frac{3+3}{3}[/tex]
[tex]m=\frac{6}{3}[/tex]
[tex]m=2[/tex]
We can see that y-intercept is [tex]-3[/tex], so our equation in slope-intercept would be: [tex]y=2x-3[/tex].
[tex]y-2x=2x-2x-3[/tex]
[tex]y-2x=-3[/tex]
[tex]y-2x+3=-3+3[/tex]
[tex]-2x+y+3=0[/tex]
[tex]-1(-2x+y+3=0)[/tex]
[tex]-1*-2x-1*y-1*3=0[/tex]
[tex]2x-y-3=0[/tex]
Therefore, our required equation is [tex]2x-y-3=0[/tex]
