Respuesta :

[tex]\bf \cfrac{\quad \frac{\stackrel{\textit{}}{x^2-16}}{x-1}\quad }{x+4}\implies \cfrac{\quad \frac{\stackrel{\textit{difference of squares}}{x^2-4^2}}{x-1}\quad }{x+4}\implies \cfrac{\quad \frac{(x-4)(x+4)}{x-1}\quad }{x+4} \\\\\\ \cfrac{\quad \frac{(x-4)(x+4)}{x-1}\quad }{\frac{x+4}{1}}\implies \cfrac{(x-4)\underline{(x+4)}}{x-1}\cdot \cfrac{1}{\underline{x+4}}\implies \cfrac{x-4}{x-1}[/tex]
vijayhalder031

When we divide (x^2-16/x-1)/x+4 the answer will be [tex]\frac{x-4}{x-1}[/tex]

What is quadratic equation?

  • In algebra, a quadratic equation is any equation that can be rearranged in standard form as where x represents an unknown, and a, b, and c represent known numbers, where a ≠ 0. If a = 0, then the equation is linear, not quadratic, as there is no ax^2 term
  • The polynomial equation whose highest degree is two is called a quadratic equation.
  • A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared.

How to solve this problem?

The steps are as follow:

  • The division of (x^2-16/x-1) by x+4 is as follow:

[tex]\frac{\frac{x^2-16}{x-1} }{x-4}\\\\\frac{x^2-4^2}{(x-1)(x-4)}\\\\ \frac{(x-4)(x+4)}{(x-1)(x-4)}\\\\ \frac{x+4}{x-1}[/tex]

So when we divide (x^2-16/x-1)/x+4 the answer will be [tex]\frac{x-4}{x-1}[/tex]

Learn more about quadratic equation here:

https://brainly.com/question/1214333

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