We know that the formula for molarity is [tex]Molarity= \frac{moles}{L} [/tex].
We are given 100g of [tex] CaCl_{2} [/tex], and the volume of water that is used is 0.850 L.
**Note: [tex] cm^{3} [/tex] = 1 mL, and there are 1000 mL in 1 L; thus, we have 0.850 L that we are dealing with in this solution.
They also give us the molar mass of [tex] CaCl_{2} [/tex], which helps us to determine the amount of moles that we are dealing with. Let's solve for how many moles of [tex] CaCl_{2} [/tex] we have:
[tex]100g* \frac{mol}{110.98g}=0.90mol [/tex].
**Another Note: The reason that I put the grams on the bottom of the fraction is because we want the grams to cancel out so that we are then left with moles.
We now know that we are dealing with 0.90 moles of [tex] CaCl_{2} [/tex], and we have 0.850 L of water for this solution. We now have enough information to solve for the concentration:
[tex]Molarity= \frac{0.90mol}{0.850L} [/tex]
[tex]Molarity =1.06 M[/tex]
The concentration of the solution is 1.06 M.
