Answer:
Molarity = 0.4 mol.L⁻¹
Solution:
Molarity is given as,
Molarity = Moles / Volume of Solution
Also,
Moles = Mass / M.mass
So,
Molarity = Mass / (M.mass × Volume of Solution)
Data Given,
Mass = 89 g
M.mass of Na₂SO₄ = 142 g.mol⁻¹
Volume = 1.5 L
Putting Values,
Molarity = 85 g ÷ (142 g.mol⁻¹ × 1.5 L)
Molarity = 0.399 ≈ 0.4 mol.L⁻¹
