Respuesta :

CastleRook
To get the solution of the quadratic equation we factorize it as follows:
6x^2+2x-20=0
factoring the above we get:
6x^2-10x+12x-20=0
2x(3x-5)+4(3x-5)=0
(2x+4)(3x-5)=0
hence the root are:
(2x+4) and (3x-5)
thus the zeros are:
2x+4=0
x=-2
3x-5=0
3x=5
x=5/3
hence the answer is x=-2 or x=5/3

abidemiokin

The solutions of the given quadratic equations is 5/3 and -2

Given the quadratic function expressed as:

  • 6x^2 + 2x – 20 = 0

Factorizing the function we will have:

6x^2 + 2x – 20 = 0

3x^2 + x - 10 = 0

3x^2 +6x - 5x - 10 = 0

3x(x+2)  5(x+2) = 0

Group the function;

(3x-5)(x+2) = 0

Find the factors

3x- 5 = 0 and x + 2 = 0

x = 5/3 and -2

The solutions of the given quadratic equations is 5/3 and -2

Learn more on factorization here: https://brainly.com/question/25829061

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