Complete Question is attached below,
Answer:
Option-A is the correct answer.
Explanation:
As we know Hydroxide contains one hydrogen and one oxygen atom. Also one negative charge is being carried bu hydroxide ion as,,,
OH⁻
Now in order to draw its lewis structure we first of all calculate the total number of valence electrons of both elements i.e.
Valence electrons in Oxygen = 6
valence electrons in Hydrogen = 1
Number of negative charges = 1
------------
Total valence electrons 8
Now, we draw both elements and connect them via a single bond and subtract 2 electrons per single bond,
= 8 - 2
= 6
Now these six electrons are added to oxygen atom as it is more electronegative element. Hence, a structure shown in Option-A is formed, and the negative charge is in fact the -1 formal charge of oxygen atom.
