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A spinner is divided into four equal sections that are numbered 2, 3, 5, and 6. The spinner is spun twice.

How many outcomes have a product less than 14 and contain at least one odd number?



4

5

6

7

Respuesta :

asadullahgiki
As the spinner is spun twice the order pairs which have a product less than 14 and contain at least one odd number are ( 2,3), ( 2,5), ( 3,2), ( 3,3), ( 5,2) 
= 5 order pairs
Option B is correct

Note: see the attached image to comprehend how we find order pair( for beginner   
Ver imagen asadullahgiki
facundo3141592

The total number of outcomes that meet the conditions are 5.

How many outcomes meet the conditions?

One of the conditions is that we must have, at least, one odd number, and the product must be smaller than 14.

Then if we define the notation for the outcomes:

Spin 1, Spin 2 ⇒ product.

The ones that meet the conditions are:

  • 2, 3 ⇒ 2*3 = 6
  • 2, 5 ⇒ 2*5 = 10
  • 3, 2 ⇒ 3*2 = 6
  • 3, 3 ⇒ 3*3 = 9
  • 5, 2 ⇒ 5*2 = 10

So we can see that there are 5 outcomes that meet the conditions.

If you want to learn more about outcomes:

https://brainly.com/question/10837034

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