contestada

A ship travels 10 miles from Point A to Point B, makes a turn of 106 degrees, and travels 14 miles to Point C. If the ship travels directly from Point C back to Point A, how many miles will it travel on the last leg of the trip (from Point C to Point A)? Round your answer to the nearest tenth of a mile.

Respuesta :

musiclover10045
See the attached picture for the solution:
Ver imagen musiclover10045

Answer:

19.32 miles

Step-by-step explanation:

AB =10 miles

∠ABC = 106°

BC = 14 miles

Now we are supposed to find AC

We will use cosine law

[tex]c^2=a^2+b^2-2ab cos C[/tex]

[tex]AC^2=AB^2+BC^2-2(AB)(BC) cos 106^{\circ}[/tex]

[tex]AC^2=100+196+77.1784596[/tex]

[tex]AC^2=373.1784596[/tex]

[tex]AC=\sqrt{373.1784596}[/tex]

[tex]AC=19.31782[/tex]

Thus it will travel 19.32 miles on the last leg of the trip .

Ver imagen wifilethbridge

Otras preguntas