Respuesta :

x^3 +2*x^2 -11*x -12 = 0 => 
=> x^3 +2*x^2 -11*x -12 = 0 
=> (x -3)*(x +4)*(x +1) = 0 

the roots are 3,-4,-1 

I just add them, 
3+(-4)+(-1)=-2

The required roots of the equation [tex]F(x)=x^3+2x^2-11x-12[/tex]  is  -1, -4, and 3.

Given that,
[tex]F(x)=x^3+2x^2-11x-12[/tex]
The root of the above polynomial function is to be determined.

What is the equation?

The equation is the relationship between variables and represented as y = ax + c   is an example of a polynomial equation.

What is a polynomial function?

A polynomial function is a function that applies only integer dominions or only positive integer powers of a value in an equation such as the quadratic equation, cubic equation, etc. ax+b is a polynomial.

Here, In order to find out the root of the equation, we have to factorize the given polynomial function,

Let, [tex]x^3+2x^2-11x-12 = 0[/tex]

[tex]x(2^2+ 2x - 11) - 12=0\\x(x^2 + 2x + 1 - 1 - 11) -12=0\\x[(x+1)^2 - 12] - 12 = 0\\x(x+1)^2-12x - 12=0\\x(x+1)^2 -12(x+1)= 0\\(x+1)(x^2 + x -12)=0\\(x+1)(x^2+4x-3x-12)=0\\(x+1)(x+4)(x-3)=0[/tex]

Now,
x + 1 = 0    ; x + 4 = 0    ; x - 3 = 0
x = -1         ; x = -4         ;  x = 3

Thus, the required roots of the equation [tex]F(x)=x^3+2x^2-11x-12[/tex]  is  -1, -4, and 3.

Learn more about the equation here:

brainly.com/question/10413253

#SPJ5