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skyluke89
The index of refraction of ethyl alcohol is n=1.36. The index of refraction of a material gives the ratio between the speed of light in vacuum and the speed of light in that material, v:
[tex]n= \frac{c}{v} [/tex]
therefore, since we know the values of n and c, we can find the speed of light in ethyl alcohol by re-arranging the equation:
[tex]v= \frac{c}{n}= \frac{3 \cdot 10^8 m/s}{1.36}=2.2 \cdot 10^8 m/s [/tex]

snehashish65

Different medium has the tendency to bend the incoming rays to a different extent. The speed of light in the ethyl alcohol medium is [tex]2.2 \times 10^{8} \;\rm m/s[/tex].

What is Refractive Index?

When a light ray travels from one medium to another, then the extent of bending of the ray of light is known as a refractive index of the medium.

Given data -

The frequency of the light wave is, [tex]f=5.09 \times 10^{14} \;\rm Hz[/tex].

The index of refraction of ethyl alcohol is n=1.36. The index of refraction of material gives the ratio between the speed of light in a vacuum and the speed of light in that material is v. Then,

n = c/v

Here, c is the speed of light in a vacuum. Solving as,

[tex]v=\dfrac{c}{n}\\\\v=\dfrac{3 \times 10^{8}}{1.36}\\\\v=2.2 \times 10^{8} \;\rm m/s[/tex]

Thus, we can conclude that the speed of light in the ethyl alcohol medium is [tex]2.2 \times 10^{8} \;\rm m/s[/tex].

Learn more about the refractive index here:

https://brainly.com/question/17156275

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