I assume L=120 yards as the length of the football field.
1) The average speed is given by the total distance covered by the player divided by the time taken.
The total distance covered to go from one goal line to the other and then back to the 40-yards line is
[tex]S=120y+(120-40)y=120y+80y=200 y[/tex]
And the time taken is t=22.4 s, so the average speed of the player is
[tex]v= \frac{S}{t}= \frac{200 y}{22.4 s}=8.93 y/s [/tex]
2) The find the average velocity, we should also consider the direction (and the sign) of the velocity.
In the the first part of the motion, the player goes from one goal line to the other one, so he covers 120 y. However, in the second part of the motion he goes back by 80 y. Therefore, the net displacement of the player is
[tex]S=120 y-80 y=40 y[/tex]
and so, the average velocity is
[tex]v= \frac{S}{t}= \frac{40 y}{22.4 s}= 1.79 y/s [/tex]
