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in a sixth term of an arithmetic progression is 37 and the sum of the first six terms is 147, find the first term and the 15th term

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tysonjeanette8p52jwr
the sixth term of an arithmetic progression is 37
---> a+5d = 37
5d = 37-a

sum of the first six term is 147
---> (6/2)(2a + 5d) = 147
3(2a + 37-a) = 147
a +37 = 49
a = 12
d = 5

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