Choose the trigonometric function that you would use to solve for x in each right triangle.

A [tex] \frac{8}{x} =sin 67^{0} [/tex], then [tex]x= \frac{8}{sin67^{0} } [/tex]
B [tex] \frac{x}{7} =tg 73^{0} [/tex], then [tex]x=7tg 73^{0} [/tex]
C [tex] \frac{x}{12} =cos 70^{0} [/tex], then [tex]x=12cos 70^{0} [/tex]
D [tex]tg x^{0}= \frac{7}{3} [/tex], then [tex]x=tg^{-1} \frac{7}{3} [/tex]
E [tex]sin x^{0}= \frac{7}{10} [/tex], then [tex]x=sin^{-1} \frac{7}{10} [/tex]
F [tex] \frac{x}{10} =cos 25^{0} [/tex], then [tex]x=10cos 25^{0} [/tex]
G [tex]sin x^{0}= \frac{7}{8} [/tex], then [tex]x=sin^{-1} \frac{7}{8} [/tex]
H [tex] \frac{x}{11} =ctg 75^{0} [/tex], then [tex]x=11ctg 75^{0} [/tex]
I [tex] \frac{x}{12} =sin 25^{0} [/tex], then [tex]x=12sin 25^{0} [/tex]
J [tex]cos x^{0}= \frac{9}{15} [/tex], then [tex]x=cos^{-1} \frac{9}{15} [/tex]
K [tex] \frac{x}{20} =cos 45^{0} [/tex], then [tex]x=20cos 45^{0} [/tex]

batolisis batolisis · Answer 2 · 2022-05-25T12:44:25+02:00

The trigonometric function that would be used to solve for x in each right angle triangle are :

1. shape A = sine

2. shape B = tangent

3. shape C = cosine

4. shape D = tangent

5. shape E = sine

6. shape F = cosine

7. shape G = sine

8. shape H = tangent

9. shape I = sine

10. shape J = cosine

11. shape K = cosine

What is a right angle triangle?

A right angled triangle is a triangle that has one of its angle 90 degrees.

it has two sides form the right angle and are called adjacent sides while the third side is called the hypotenuse.

Analysis:

shape A, x is the hypotenuse side and 8 is the opposite, the ratio of the opposite side to the hypotenuse is sine of the angle facing the opposite side.

Shape B, x is the opposite and 7cm is the adjacent, the ratio of the opposite side to the adjacent side is the tangent of the angle facing the opposite side.

shape C, x is the adjacent and 7cm is the hypotenuse, the ratio of the adjacent side to the hypotenuse is the cosine of the angle facing the opposite side.

shape D, 7cm is the opposite and 3cm is the adjacent, the ratio of the opposite side to the adjacent side is the tangent of the angle facing the opposite side.

shape E, 10cm is the hypotenuse side and 7cm is the opposite, the ratio of the opposite side to the hypotenuse is sine of the angle facing the opposite side.

shape F, x is the adjacent and 10cm is the hypotenuse, the ratio of the adjacent side to the hypotenuse is the cosine of the angle facing the opposite side.

shape G, 8cm is the hypotenuse side and 7cm is the opposite, the ratio of the opposite side to the hypotenuse is sine of the angle facing the opposite side.

shape H, 11cm is the opposite and x is the adjacent, the ratio of the opposite side to the adjacent side is the tangent of the angle facing the opposite side.

shape I, 12cm is the hypotenuse side and x is the opposite, the ratio of the opposite side to the hypotenuse is sine of the angle facing the opposite side.

shape J, 9cm is the adjacent and 15cm is the hypotenuse, the ratio of the adjacent side to the hypotenuse is the cosine of the angle facing the opposite side.

shape K, x is the adjacent and 20cm is the hypotenuse, the ratio of the adjacent side to the hypotenuse is the cosine of the angle facing the opposite side.

in conclusion, the trigonometric functions suitable for the drawn shapes are as listed above

Learn more about trigonometric functions: brainly.com/question/24349828

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