Respuesta :
About 31.5% when rounded.
This is because you have to start with the probability of each urn. The first urn has 13 total balls (5 white and 8 yellow). Since 5 of them are white, the odds of pulling a white ball are 5/13. Then find the same for the second urn (9 white and 2 yellow). Therefore there are 11 total balls and 9/11 chance of getting a white one. After finding both, multiply them together to get the answer.
[tex] \frac{5}{13} [/tex] * [tex] \frac{9}{11} [/tex] = [tex] \frac{45}{143} [/tex] = 31.5%
This is because you have to start with the probability of each urn. The first urn has 13 total balls (5 white and 8 yellow). Since 5 of them are white, the odds of pulling a white ball are 5/13. Then find the same for the second urn (9 white and 2 yellow). Therefore there are 11 total balls and 9/11 chance of getting a white one. After finding both, multiply them together to get the answer.
[tex] \frac{5}{13} [/tex] * [tex] \frac{9}{11} [/tex] = [tex] \frac{45}{143} [/tex] = 31.5%
For the first urn:
p(white ball) = 5/13
For the second urn:
p(white ball) = 9/11
Since the two drawings are independent events, the probability of both happening is the product of the individual probabilities.
p(drawing two white balls) = 5/13 * 9/11 = 45/143
p(white ball) = 5/13
For the second urn:
p(white ball) = 9/11
Since the two drawings are independent events, the probability of both happening is the product of the individual probabilities.
p(drawing two white balls) = 5/13 * 9/11 = 45/143