Answer:
The reference angle will be [tex]{\theta}=45^{\circ}[/tex]
Step-by-step explanation:
To solve for [tex]sin(-135)[/tex], the reference angle can be obtained as follows:
= [tex]sin(-135)[/tex]
=[tex]- sin(135)[/tex] (Because [tex]sin(-{\theta})=-sin{\theta}[/tex])
Thus, the above equation can be written as:
=[tex]-sin(180-135)[/tex]
=[tex]-sin45[/tex]
Hence
, the reference angle will be [tex]{\theta}=45^{\circ}[/tex]
