Respuesta :
Let the width of rectangular frame is x cm. It is given that the frame is 6 cm longer than it is wide. Therefore, the length of the frame will be (x + 6) cm.
A frame of 1 cm is placed all around the picture. This will increase the length and width of the frame from all four sides by 1 cm.
So, the new width will be (x + 2) cm and the new length will be (x +8) cm.
Area of rectangle = Length x Width
So, area of rectangular frame will be (x+2)(x+8) square centimeters.
Simplifying the expression we get:
Area = [tex] x^{2} +2x+8x+16[/tex]
Area = [tex] x^{2} +10x+16[/tex]
The above polynomial represents the Area of the frame.
A frame of 1 cm is placed all around the picture. This will increase the length and width of the frame from all four sides by 1 cm.
So, the new width will be (x + 2) cm and the new length will be (x +8) cm.
Area of rectangle = Length x Width
So, area of rectangular frame will be (x+2)(x+8) square centimeters.
Simplifying the expression we get:
Area = [tex] x^{2} +2x+8x+16[/tex]
Area = [tex] x^{2} +10x+16[/tex]
The above polynomial represents the Area of the frame.
The area of the rectangular frame is (4w + 18) cm²
Area
Area is the amount of space occupied by a two dimensional figure or object.
Let w represent the width of the picture, hence length = w + 6
Area of picture = w(w + 6) = w² + 6w
If a frame of 1 cm is used,:
Length of picture and frame = w + 6 + 2(1) = w + 8, Width of picture and frame = w + 2(1) = w + 2
Area of picture and frame = (w + 8)(w + 2) = w² + 10w + 18
Area of frame = w² + 10w + 18 - (w² + 6w) = 4w + 18
The area of the rectangular frame is (4w + 18) cm²
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