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A company produces individually wrapped spherical biscuits. The minimum amount of wrapping material needed to cover a biscuit, assuming no edges overlap, is 200.96 square centimeters. What is the diameter of one biscuit? (Use 3.14 for the value of π.)

Respuesta :

The minimum amount of wrapping material needed to cover a biscuit would be equal to the biscuit area. The biscuit is spherical/circle, so the area would be using circle formula. If the area is 200,96, the radius would be:
circle area = π * r * r
200.96= 3.14 * r^2
r^2=200.96/3.14
r= √64= 8

The diameter would be: 
diameter = radius *2
diameter= 8*2= 16

Answer:

C: 16

Step-by-step explanation:

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