For transfomers (robots in disguise), there are equations to help us solve these problems.
Here are the equations you need:
[tex] \frac{V_{p}}{V_{s}}= \frac{n_{p}}{n_{s}}[/tex]
[tex]V_{p}[/tex] is our V primary, [tex]v_{s}[/tex] is our V secondary, [tex]n_{p}[/tex] is our number of loops on our primary and [tex]n_{s}[/tex] is number of loops in our secondary.
Plugging our known values in, we can solve for the secondary voltage.
[tex] \frac{220}{V_{s}}= \frac{55}{440} [/tex]
[tex]V_{s} = 1760V[/tex]
For current, we have another equation:
[tex]V_{p}I_{p}=V_{s}I_{s}[/tex]
Just like before, we can plug in our known values:
[tex](220V)(4A)=(1760V)I_{s}[/tex]
[tex]I_{s}= 0.5A[/tex]
Since we are told there are no losses, the input power must equal output power.
(0.5A)(1760V)=(220V)(4A) = 880W
