To find the area of this figure, let's first split this into two triangles by drawing a vertical line from point B down to the bottom of the figure. We then have two triangles:
One triangle with a base of 6 units and a height of 6 units
And a second triangle with a base of 1 unit and a height of 6 units
We know that to find the area of a triangle, we must use the equation:
[tex]A= \frac{1}{2}bh [/tex]
So let's solve for the first triangle:
[tex]A= \frac{1}{2}(6)(6)=18 units^{2} [/tex]
The let's solve for the second triangle:
[tex]A= \frac{1}{2}(1)(6)=3 units^{2} [/tex]
Now to find the total area of the figure, let's add them together:
[tex] 18units^{2}+ 3units^{2} = 21units^{2} [/tex]
Now we know that the area of this figure is [tex] 21 units^{2} [/tex].
