Answer:
3.2 g of O₂
Solution:
This reaction is for the formation of Potassium Superoxide, The reaction is as follow,
K + O₂ → KO₂
First let us confirm that either the given amount of Potassium produces the given amount of Potassium oxide or not,
So,
As,
39.098 g (1 mole) K produced = 71.098 g of K₂O
So,
3.91 g of K will produce = X g of K₂O
Solving for X,
X = (3.91 g × 71.098 g) ÷ 39.098
X = 7.11 g of K₂O
Hence, it is confirmed that we have selected the right equation,
So,
As,
39.098 g of K required = 32 g of O₂
So,
3.91 g of K will require = X g of O₂
Solving for X,
X = (3.91 g × 32 g) ÷ 39.098 g
X = 3.2 g of O₂
