XZ is a common external tangent to circles W and Y. What is the distance between the two centers of the circles? Round to the nearest hundredth.

Construct a triangle by drawing a line parallel to XZ at Center W; intersecting the radius from Center Y to Z.
It is a right-angled triangle with one side at the same length as XZ = 42.
Length of the other side of the right-angle is the difference in radius = 19-11 = 8
Distance between centers = length of hypothesis
= sqrt(42^2 + 8^2)
= 42.755 = 42.76
By Pythagoras Theorem the distance between the two centers of the circles exists at 42.8 units.
Given:
XZ exists as a common external tangent to circles W and Y.
In the right triangle WYS
By using the Pythagoras Theorem
[tex]$W Y^{2}=W S^{2}+Y S^{2}$[/tex]
we have,
Y Z = 19, WX = 11
WS = XZ = 42 units
YS = Y Z - WX
= 19 - 11 = 8 units
substitute the value in WY,
[tex]$W Y^{2}=42^{2}+8^{2}$[/tex]
[tex]$W Y^{2}=1,828$[/tex]
WY = 42.8 units
The distance between the two centers of the circles exists at 42.8 units.
By using Pythagoras Theorem the distance between the two centers of the circles exists at 42.8 units.
To learn more about Pythagoras Theorem
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