Part 3) Given triangle XYZ as shown at right find YZ rounded to the nearest tenth
we know that the sum of the internal angles of a triangle add up to 180 degrees so m∠X=180-[55+29]----> 96° applying the law of sines YZ/sin X=35/sin 55°------> YZ=35*sin 96/sin 55-----> YZ=42.49 YZ=42.5 units
the answer Part 3) is YZ=42.5 units
Part 4) we know that OQ/NQ=PR/NR NQ=4X+(2X+2)---> 6X+2 OQ=2X+2 PR=15 NR=24+15----> 39 (2X+2)/(6X+2)=15/39 39*(2X+2)=15*(6X+2) 78X+78=90X+30 90X-78X=78-30 12X=48 X=4
The answer part 4) is x=4
Part 5) A trapezoid is show below. Calculate the measure of angle x. Round to the nearest tenth of a degree
see the picture with letters attached to better understand the problem
we know that BC=36-28-----> 8 ft
sin x=BC/AC-----> sin x=8/12 x=arc sin(8/12)-------> x=41.81°------> x=41.8°
