phiza4113
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What is the equation of the tangent line to the curve y = 6x - x2 - 5 at the point (4,3)?

A. 2x + y = 11
B. x - y = 1
C. 2x -y = 5
D. x + y = 7

also please please please explain how you got your answer! I swear, I have never had problem with anything in my life as hard as I have with calculus

Respuesta :

dy/dx = 6 - 2x

dy/dx evaluated at x = 4

= 6-2(4) = -2

y-3 = -2(x-4)

y-3=-2x+8

y = -2x + 11

2x+y=11, so the answer is A

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