Answer:
No solution
Step-by-step explanation:
We are given some dimension of triangle.
a=6
∠A=110°
b=10
Using sine law, we will find rest part of the triangle.
[tex]\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}[/tex]
Substitute the value into formula
[tex]\dfrac{6}{\sin 110^\circ}=\dfrac{10}{\sin B}=\dfrac{c}{\sin C}[/tex]
[tex]\dfrac{6}{\sin 110^\circ}=\dfrac{10}{\sin B}[/tex]
[tex]\sin B=1.56[/tex]
[tex]\angle B=\sin^{-1}(1.56)[/tex]
[tex]\angle B=\text{Not Possible}[/tex]
Because value of sine can't be more than 1.
No solution for triangle. No such triangle form.
Hence, The number of triangle for given info is zero
