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tdpuppies14
To find the total area of this polygon, you would have to find the areas of the rectangle and two triangles and add them up. 

Area of Triangle = 1/2 x base x height
= 1/2 x 16 x 6
= 8 x 6
= 48

And since there are two triangles, we can multiply 48 by 2 to get the areas of both triangles.

Area of Both Triangles = 48 x 2 = 96
Area of Rectangle = base x height
= 16 x 10 = 160

Total Area = 96 + 160 = 256 cm2
limacharliesierra
The figure is composed by 2 Isosceles Triangles (Two equal sides) and one Rectangle in the middle.

Triangle Area:
[tex]base \times height \div 2[/tex]
Rectangle Area:
[tex]length \times width[/tex]
- Triangles:
Base: 16cm
Height: 6cm

- Rectangle:
Length: 16cm
Width: 10cm

Triangle Area (At):

- At = 16 x 6/2
- At = 96/2
- At = 48 cm^2

Rectangle Area (Ar):

- Ar = 16 x 10
- Ar = 160 cm^2

Total Area = 2 x (Triangle Area) + Rectangle Area

Total Area = 2 x 48 + 160
Total Area = 96 + 160
Total Area = 256cm^2

Answer: 256cm^2, last alternative.

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