Respuesta :

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[tex]f(x)=2x+1\\\\g(x)=2\left[f(x)\right]^2-1\\\\g(x)=2\cdot(2x+1)^2-1=2\cdot[(2x)^2+2\cdot2x\cdot1+1^2\right]-1\\\\=2\cdot(4x^2+4x+1)-1=8x^2+8x+2-1=8x^2+8x+1[/tex]

Used:  [tex](a+b)^2=a^2+2ab+b^2[/tex]
shubhamchouhanvrVT

The value of the function will be equal to g(x) = 8x² + 8x + 1 .

What is a function?

A function is defined as the expression that set up the relationship between the dependent variable and independent variable.

The solution to the function will be given as follows:-

g ( x )  =  2  [ f ( x ) ]² - 1

g ( x )  =  2  [   ( 2x  +  1 )  ]² - 1

g  ( x ) =  2  [   ( 4x²  +  4x   +  1    ] -  1  )

g  ( x ) =  8x² + 8x + 2 - 1

g  (  x )  =   8x² + 8x + 1

Therefore the value of the function will be equal to g(x) = 8x² + 8x + 1

To know more about function follow

https://brainly.com/question/25638609

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